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trigonometry - $\tan(x)=\cot(90^\circ-x)$?? - Mathematics Stack

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I was looking at a mark scheme for a question I was stuck on, and I came across this. You are asked to work out the value of $\tan 75^\circ$ after you've worked out $\cos 15^\circ$ and $\sin 15^\ci

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Tan (90- Ө) = Cot Ө and Cot (90- Ө) = Tan Ө

cot(90 + x), cot(90 + A), cot(90 + theta), Identity for cot(90 + x)

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